Chicago Jack Service, Inc. Members of: ESA, Stafda, AISE Members of: ESA, Stafda, AISE Members of: ESA, Stafda, AISE Members of: ESA, Stafda, AISE
We Service What We Sell
Hydraulic Products
» Basic Hydraulics
» Cylinders
» Jacks
» Post Tensioning Cylinders
» Presses
» Pumps
» Rebar Grippers / Testers
» Synchronous Lift System
» Torque Wrenches

Contact Info
Chicago Jack Service
2000 S. 25th Ave, STE T
Broadview, IL 60155 USA
Phone: 708-681-1800
Fax: 708-681-1900

  • Capacities Ranging from 20 cubic inches to 25 gallons
  • Lightweight Hand Pumps
  • Steel Hand Pumps
  • Low Pressure / High Flow Pumps
  • Ultra High Pressure Pumps
  • Electric Pumps
  • Air Pumps
  • Gasoline Pumps
    New ZG-Series Gas Pumps
  • Capacities Ranging from 5 Ton to 1000 Ton
  • Single Acting Cylinders
  • Double Acting Cylinders
  • Hollow Plunger Cylinders
  • Lock Nut Cylinders
  • Aluminum Cylinders
  • Low Height Cylinders
*Custom made cylinders also available upon request
  • Chrome plated plungers
  • Machined flat front and bottom surfaces permit flush alignment in tight corners
  • Internal relief valve to prevent overloading
  • All models include pumping handle
  • Two-directional operation (vertical and horizontal)
Torque Wrenches Square Drive 3/4" to 2-1/2" square drive
  • 1400 ft lbs. to 25,400 ft lbs.
  • Imperial and Metric Allen Key Drives Available
Hexagon Cassette Wrenches Hexagon Cassette Wrenches
  • Cassette Ranges 1-1/4"-5"
  • Imperial and Metric Inserts/Reducers Available
  • Unique Auto cycle feature provides continuous cycle operation of the torque wrench as long as the advance button is pressed. (Pump can be used with or without auto cycle feature)
  • Optional with 4 wrench manifold for simultaneous multi-wrench operation
*Demos available.
  • Quality welded H-frame for maximum strength and stability
  • Manual, air or electric driven power sources
  • Available with single or double-acting cylinder
  • Side movement of cylinder (on 10 and 25 ton)
  • Unique "Hydrajust" bed positioning device on 50, 100 and 200 ton presses equipped with double-acting cylinders
Synchronous Lift System
  • Up to 64 lifting points, load and stroke controlled
  • Capacities from 10 up to 1000 ton per lifting point
  • Up to .004 inch accuracy over full stroke
  • PLC-controlled user friendly touch screen
  • Automatic data storage and read-out for reporting and graphical presentation
  • System security with warning and stop features for optimum safety
  • 10,000 psi maximum operating pressure
  • Many optional System Management & Control Feature
sls diagram
  1. Hydraulic pump
  2. PLC-control with touch screen
  3. Hydraulic cylinders
  4. Stroke sensors
  5. Hydraulic hoses
  6. Sensor cables
  7. Solenoid control valves
  8. Pressure transducer
Rebar Grippers / Testers
  • Quick Acting
  • Sizes #4 thru #18
  • Available for Sale and Rental

Quick acting grips are perfect for pullout testing of grouted re-bar on highway, bridge and tunnel applications.

When used with hydraulic jack, just slip jack and grip over grouted re-bar and apply pressure to desired load (available with hydraulic jack system).

Also grips available for rigging and special applications.











#4 thru #18









#9 thru #18








Post Tensioning Cylinders
Basic Hydraulics
Flow A hydraulic pump produces flow Pressure Pressure occurs when there is resistance to flow



Pascal's Law    
Pressure applied at any point upon a confined liquid is transmitted undiminished in all directions (Fig.1). This means that when more than one hydraulic cylinder is being used, each cylinder will lift at its own rate, depending on the force required to move the load at that point (Fig. 2). Cylinders with the lightest load will move first, and cylinders with the heaviest load will move last (Load A), as long as the cylinders have the same capacity.

Figure 1

To have all cylinders operate uniformly so that the load is being lifted at the same rate at each point, either control valves (see Valve section) or Synchronous Lift System components (see Cylinder section) must be added to the system (Load B).

Figure 2  Synchronous Lift or Control Valves to provide uniform lifting of load.

Force The amount of force a hydraulic cylinder can generate is equal to the hydraulic pressure times the “effective area” of the cylinder (see cylinder selection charts).






Example 1
An RC-106 cylinder with 2.24 in2 effective area operating at 8,000 psi will generate what force?
Force = 8,000 psi x 2.24 in2 = 17,920 lbs.

Example 2
An RC-106 cylinder lifting 14,000 lbs will require what pressure?
Pressure = 14,000 lbs ÷ 2.24 in2 = 6,250 psi.

Example 3
An RC-256 cylinder is required to produce a force of 41,000 lbs.
What pressure is required?
Pressure = 41,000 lbs. ÷ 5.15 in2 = 7961 psi.

Example 4
Four RC-308 cylinders are required to produce a force of 180,000 lbs. What pressure is required?
Pressure = 180,000 lbs ÷ (4 x 6.49 in2) = 6933 psi. Remember, since four cylinders are used together, the area for one cylinder must be multiplied by the number of cylinders used.

Example 5
A CLL-2506 cylinder is going to be used with a power source that is capable of 7,500 PSI. What is the theoretical force available from that cylinder?
Porce = 7,500 psi x 56.79 in2 = 425,925 lbs.




Cylinder Oil The volume of oil required for a cylinder (cylinder oil capacity) is equal to the effective area of the cylinder times the stroke*.


Note: these are theoretical examples and do not take into account the compressibility of oil under high pressure.

Example 1
An RC-158 cylinder with 3.14 in2 effective area and an 8 in stroke will require what volume of oil?
Oil Capacity = 3.14 in2 x 8 in = 25.12 in3

Example 2:
An RC-5013 cylinder has an effective area of 11.05 in2 and a stroke of 13.25 in. How much oil will be required?
Oil Capacity = 11.05 in2 x 13.25 in = 146.41 in3

Example 3:
An RC-10010 cylinder has an effective area of 20.63 in2 and a stroke of 10.25 in. How much oil will it require?
Oil Capacity = 20.63 in2 x 10.25 in = 211.46 in3

Example 4:
Four RC-308 cylinders are being used, each with an effective area of 6.49 in2 and stroke of 8.25 in. How much oil will be required?
Oil Capacity = 6.49 in2 x 8.25 in = 53.54 in3 for one cylinder
Multiply by four to obtain the required capacity: 214.17 in3

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