RENTAL  SALES  SERVICE
 Capacities Ranging from 20 cubic inches to 25 gallons
 Lightweight Hand Pumps
 Steel Hand Pumps
 Low Pressure / High Flow Pumps
 Ultra High Pressure Pumps
 Electric Pumps
 Air Pumps
 Gasoline Pumps
New ZGSeries Gas Pumps
 Capacities Ranging from 5 Ton to 1000 Ton
 Single Acting Cylinders
 Double Acting Cylinders
 Hollow Plunger Cylinders
 Lock Nut Cylinders
 Aluminum Cylinders
 Low Height Cylinders
*Custom made cylinders also available upon request
 Chrome plated plungers
 Machined flat front and bottom surfaces permit flush alignment in tight corners
 Internal relief valve to prevent overloading
 All models include pumping handle
 Twodirectional operation (vertical and horizontal)
 Quality welded Hframe for maximum strength and stability
 Manual, air or electric driven power sources
 Available with single or doubleacting cylinder
 Side movement of cylinder (on 10 and 25 ton)
 Unique "Hydrajust" bed positioning device on 50, 100 and 200 ton presses equipped with doubleacting cylinders
 Up to 64 lifting points, load and stroke controlled
 Capacities from 10 up to 1000 ton per lifting point
 Up to .004 inch accuracy over full stroke
 PLCcontrolled user friendly touch screen
 Automatic data storage and readout for reporting and graphical presentation
 System security with warning and stop features for optimum safety
 10,000 psi maximum operating pressure
 Many optional System Management & Control Feature
 Hydraulic pump
 PLCcontrol with touch screen
 Hydraulic cylinders
 Stroke sensors
 Hydraulic hoses
 Sensor cables
 Solenoid control valves
 Pressure transducer
 Quick Acting
 Sizes #4 thru #18
 Available for Sale and Rental
Quick acting grips are perfect for pullout testing of grouted rebar on highway, bridge and tunnel applications.
When used with hydraulic jack, just slip jack and grip over grouted rebar and apply pressure to desired load (available with hydraulic jack system).
Also grips available for rigging and special applications.
Dimension 

A 
B 
C 
D 
E 
F 
WT 
RS 
#4 thru
#18 
11/2" 
3" 
41/2" 
4" 
7" 
51/2" 
20lbs. 
RL 
#9 thru
#18 
2" 
3" 
5" 
6" 
93/4" 
73/4" 
43lbs. 
Flow 
A hydraulic pump produces flow 
Pressure 
Pressure occurs when there is resistance to flow 




Pascal's Law 


Pressure applied at any point upon a confined liquid is transmitted undiminished in all directions (Fig.1). This means that when more than one hydraulic cylinder is being used, each cylinder will lift at its own rate, depending on the force required to move the load at that point (Fig. 2). Cylinders with the lightest load will move first, and cylinders with the heaviest load will move last (Load A), as long as the cylinders have the same capacity. 
Figure 1

To have all cylinders operate uniformly so that the load is being lifted at the same rate at each point, either control valves (see Valve section) or Synchronous Lift System components (see Cylinder section) must be added to the system (Load B). 
Figure 2 Synchronous Lift or Control Valves to provide uniform lifting of load.
Force 
The amount of force a hydraulic cylinder can generate is equal to the hydraulic pressure times the “effective area” of the cylinder (see cylinder selection charts).

Example 1
An RC106 cylinder with 2.24 in2 effective area operating at 8,000 psi will generate what force?
Force = 8,000 psi x 2.24 in2 = 17,920 lbs.
Example 2
An RC106 cylinder lifting 14,000 lbs will require what pressure?
Pressure = 14,000 lbs ÷ 2.24 in2 = 6,250 psi.
Example 3
An RC256 cylinder is required to produce a force of 41,000 lbs.
What pressure is required?
Pressure = 41,000 lbs. ÷ 5.15 in2 = 7961 psi.
Example 4
Four RC308 cylinders are required to produce a force of 180,000 lbs. What pressure is required?
Pressure = 180,000 lbs ÷ (4 x 6.49 in2) = 6933 psi. Remember, since four cylinders are used together, the area for one cylinder must be multiplied by the number of cylinders used.
Example 5
A CLL2506 cylinder is going to be used with a power source that is capable of 7,500 PSI. What is the theoretical force available from that cylinder?
Porce = 7,500 psi x 56.79 in2 = 425,925 lbs. 



Cylinder Oil 
The volume of oil required for a cylinder (cylinder oil capacity) is equal to the effective area of the cylinder times the stroke*.
* 
Note: these are theoretical examples and do not take into account the compressibility of oil under high pressure. 

Example 1
An RC158 cylinder with 3.14 in2 effective area and an 8 in stroke will require what volume of oil?
Oil Capacity = 3.14 in2 x 8 in = 25.12 in3
Example 2:
An RC5013 cylinder has an effective area of 11.05 in2 and a stroke of 13.25 in. How much oil will be required?
Oil Capacity = 11.05 in2 x 13.25 in = 146.41 in3
Example 3:
An RC10010 cylinder has an effective area of 20.63 in2 and a stroke of 10.25 in. How much oil will it require?
Oil Capacity = 20.63 in2 x 10.25 in = 211.46 in3
Example 4:
Four RC308 cylinders are being used, each with an effective area of 6.49 in2 and stroke of 8.25 in. How much oil will be required?
Oil Capacity = 6.49 in2 x 8.25 in = 53.54 in3 for one cylinder
Multiply by four to obtain the required capacity: 214.17 in3 

